X^2+11x=33

Solution for X^2+11x=33 equation:

X^2+11X=33

We move all terms to the left:

X^2+11X-(33)=0

a = 1; b = 11; c = -33;
Δ = b2-4ac
Δ = 112-4·1·(-33)
Δ = 253
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{253}}{2*1}=\frac{-11-\sqrt{253}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{253}}{2*1}=\frac{-11+\sqrt{253}}{2}
$